If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.
400 ms-1
4,000 ms-1
8,000 ms-1
160,000 ms-1
Correct answer is A
The velocity of sound in air, V∝√T, where T is absolute temperature
Thus V = K√T or K = V/T
V is independent of pressure and density at a fixed temperature.
∴ V1/√T1 = V2/√T2
T1 = 16 + 273 = 289K, V1 = 340ms-1
T2 = 127 + 273 = 400K, V2 = ?
| 340 | = | V2 |
| √289 | √400 |
| ∴ V2 = | 340√400 |
| _√289 |
= 400m/s
7:5
5:7
1:2
2:1
Correct answer is C
Metals P, Q
original length lP, lQ
Increase in length ΔlP, ΔlQ
Linear expansivities αP, αQ
∴ αP/αQ = 2/3 ; and lP/lQ = 3/4
But increase in length, Δl = αlΔθ
∴ΔlP = αPlPΔθ
ΔlQ = αQlQΔθ
| ∴ | ΔlP | = | αPlPΔθ | = | 2 | x | 3 | = | 1 |
| ΔlQ | αQlQΔθ | 3 | 4 | 2 |
∴ Ratio of increase in length of P to Q = 1:2
III, IV and VIII
II, V and VIII
III, VI and IX
I, IV and VII
Correct answer is C
A bod y is said to be in stable equilibrium if after a slight displacement, the body returns to its former position. Thus, position III, VI and XI represents position of stable equilibrium
has no acceleration between point F and G
decelerates between F and H
has a constant soeed between points E and F
Accelerates between points F and G
Correct answer is A
Above are the V-t graphs for
I Uniform acceleration
II uniform retardation
III Uniform velocity
Thus the car has no acceleration between point F and G since that portion of the graph represents uniform velocity
116.3 V
50.0 V
230.0 V
106.3 V
Correct answer is D
V = √ \({(v_l - v_c)}^2 + V^2R\)
V =√ \({(40 - 110)}^2 + 80^2\)
V = √ \({-70}^2 + 80^2\)
=√ 4900 + 6400
=√ 11300
= 106.3v