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Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

3,671.

The terminal velocity of a ball-bearing falling through a viscous fluid is reached when the?

A.

upthrust is equal to the weight of the ball

B.

ball accelerate uniformly

C.

upthrust is equal to the velocity of the ball

D.

velocity is uniform

Correct answer is D

At vt = terminal velocity
= zero acceleration
= uniform velocity

3,672.

A body of mass 12kg traveling at 4.2ms-1 collides with a second body of mass 18kg at rest. Calculate their common velocity if the two bodies coalesce after collision?

A.

1.5 ms-1

B.

1.4 ms-1

C.

2.1 ms-1

D.

1.7 ms-1

Correct answer is D

Sum of momentum before collision
M1 U1 + M2M2
12 x 4.2 + 18 x 0
12 x 4.2
= 50.4
Sum of momentum after collision
(m1 + m2)v
= (12 + 18)v
= 30v
V = 50.4/30
= 1.7ms-1

3,673.

A car accelerate uniformly from rest at 4 ms-2. How far will it travel in the fifth complete second?

A.

100 m

B.

50 m

C.

32 m

D.

18 m

Correct answer is D

From S = ut + 1/2 at2
S = 1/2 ut2, since U = 0
Let S5 = distance in 5 seconds
= 1/2 x 4 x 52 = 2 x 25 = 50m
S4 = distance covered in 4 seconds
= 1/2 x 4 x 42 = 2 x 16 = 32m
Distance covered in the fifth second
S5 - S4 = 50m - 32m = 18m

3,674.

The value of x, y and z respectively in the expression Mx LyT z for the universal gravitational constant G are?

A.

2, -3, -2

B.

-1, 3, -2

C.

-1, 2, -3

D.

-2, -1, 3

Correct answer is B

F ∝ M1M2
__r2

 

 

=> F = GM1M2
__r2


where F is the force of attraction
M1 and M2 are masses of the two bodies, r is the distance between them, and G is the universal gravitational constant

 

 

 

∴ G = _Fr2
M1M2

 

 

∴ dimension for force, F = ML = MLT-2
T.T

 

 

The dimension for G = MLT-2L2 = L3T-2
_MM _M


= M-1L3T-2
In comparison with MxLyTz, the values for x, y and z = -1, 3, -2

 

3,675.

14 N + 4 He → 17 O + X
7 2 8


In the equation above, the particles X is?

A.

a proton

B.

a neutron

C.

an α - particle

D.

a β - particle

Correct answer is A

for the conversion of mass 14 + 4 = 17 + x
∴ X = 18 - 17 = 1
for conservation pf charge:7 + 2 = 8 + y
y = 9 - 8 = 1
Thus, the element is 11X which is equal to hydrogen nucleus ( proton)