Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

3,691.

During the nuclear reaction described by

235W →235X→231Y
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the particles emitted are respectively

A.

α and α

B.

α and β

C.

β and β

D.

β and α

Correct answer is D

The decay process illustrated above shows that the lost β -particle to decay to the X by increase its atomic number ( from 92 to 93) and leaving the mass no. unaffected. There after, x decayed by -α emission to give Y, by decreasing the mass no. by 2 ( from 93 to 91).
Thus , the emission is β and α particles respectively

3,692.

Which of the following will be applied when a metal Y is used to electroplate another metal X in electrolysis?

A.

X is the anode and very high current is used

B.

X is the anode and Y is the cathode

C.

Y is the cathode and X is the anode

D.

Y is the anode and very high current is used

Correct answer is D

Metals and hydrogen are deposited at the cathode, while non-metals and oxygen are deposited on the anode
∴ metals Y will form the anode which is deposited at the cathode made of x

3,693.

If the threshold frequency for tungsten is 1.3 x 1015Hz, what is its work function?


[H = 6.6 x 10-34 Js]

A.

8.58 x 10-19 J

B.

8.50 x 10-15 J

C.

8.58 x 10-17 J

D.

8.85 x 10-18

Correct answer is A

Work function, w = hfo 6.6 x 10-34 x 1.3 x 1015
= 8.58 x 10-19

3,694.

The electrical properties of germanium can be altered drastically by the addition of impurity. This process is referred to as

A.

saturation

B.

bonding

C.

amplification

D.

dopping

Correct answer is D

No explanation has been provided for this answer.

3,695.

A radioactive isotope has a decay constant of 10-5s4. Calculate half life

A.

6.93 x 10-5s

B.

6.93 x 105s

C.

6.93 x104s

D.

6.93 x 10-4s

Correct answer is C

T (1)/2 = (0.693)/λ = (0.693)/10-5
= 0.693 x 105
= 6.93 x 104 sec