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Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

3,686.

A force F required to keep a 5 kg mass moving round a cycle of radius 3.5 m at a speed of 7 ms-1. What is the speed, if the force is tripled?

A.

4.0 ms-1

B.

6.6 ms-1

C.

12.1 ms-1

D.

21.0 ms-1

Correct answer is C

The force which is centripetal
F = MV2R
=5 x 723.5
= 70

 

Since, force is 70 N when speed is 7m/s

Speed = ? when force 70N is trippled →  70 * 3 = 210N

210 = 5×v23.5
210 × 3.5 = 5 * v^2
735 ÷ 5 = v2
v2 = 147
v =12.12m/s

3,687.

The resultant of two forces 12N and 5N is 13N. What is the angle between the two forces?

A.

0o

B.

45o

C.

90o

D.

180o

Correct answer is C

R2 - P2 + Q2 = 122 + 52
= 144 + 25 = 169
∴R = √169 = 13N
∴ angle between the forces is 90o

3,688.

The dimension of electromotive force are?

A.

ML2T-3I-1

B.

ML2T-3I-2

C.

M2LT-2I-1

D.

M2L2T-1I-1

Correct answer is A

Electrical work W = QE,
Where Q is the quantity of change and E is the electromotive force.
∴ E = W = FxDQ_It
Where D is the displacement,I = current and t = time
But dimension of force,
= unit of mass x unit of Acceleration
= unit of mass xunit of velocityunit of time
= unit of mass x unit of displacement__unit of time x unit of time
ML/T2 = MLT-2
∴ Dimension of emf E
= MLT-2L = ML2T-3I-1__IT

3,689.

118.8cm2 surface of the copper cathode of a voltameter is to be coated with 10-6m thick copper of density 9 x 103kgm-3. How long will the process run with 10A constant current?
[3.3 x 10-7kgC-1]

A.

5.4 min

B.

10.8 min

C.

15.0 min

D.

20.0 min

Correct answer is A

From faradays law, M = itz
But mass, M = volume x density
and volume = cross sectional area x thickness
M = 118.8cm2 x 10-6 x 9 x 103
∴ 118.8cm2 x 10-6 x 9 x 103 = 10 x t x 3.3 x 10-7
∴ (118.8 x 9) x 10-7 = 10 x t x 3.3 x 10-7

∴ t = 118.8×93.3

t = 324 seconds

Convert to minutes by dividing by 60

t = 32460

t = 5.4 sec

3,690.

from the diagram above, the inductive reactance and the resistance R are respectively

A.

50Ω and 45Ω

B.

25Ω and 51Ω

C.

20Ω and 50Ω

D.

10Ω and 50Ω

Correct answer is D

The inductive reactance is given as
Xl = 2πfl
= 2 x 50/π x 0.1
= 10Ω
Again from ohms law,
R = V/I = 75/1.5 = 50Ω
∴ Thus the inductive reactance and the resistance are respectively 10Ω, and 50Ω