2x2−3x−4(x−2)(x+3)
2x2+3x−4(x−2)(x+3)
2(x−2)(x+3)
3x+4(x−2)(x+3)
3x−4(x−2)(x+3)
Correct answer is D
xx−2−x+2x+3
[x][x+3]−[x+2][x−2][x−2][x+3]
= x2+3x−x2−4[x−2][x+3]
= 3x−4[x−2][x+3]
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