\(yx^2 = 300\)
\(yx^2 = 900\)
y = \(\frac{100x}{9}\)
\(y = 900x^2\)
Correct answer is B
Y \(\alpha \frac{1}{x^2} \rightarrow y = \frac{k}{x^2}\)
If x = 3 and y = 100,
then, \(\frac{100}{1} = \frac{k}{3^2}\)
\(\frac{100}{1} = \frac{k}{9}\)
k = 100 x 9 = 900
Substitute 900 for k in
y = \(\frac{k}{x^2}\); y = \(\frac{900}{x^2}\)
= \(yx^2 = 900\)
Express \(\frac{1}{x + 1}\) - \(\frac{1}{x - 2}\) as a single algebraic fraction...
If 9x2 + 6xy + 4y2 is a factor of 27x3 - 8y3, find the other factor. ...
If \(M5_{ten} = 1001011_{two}\) find the value of M...
Arrange \(\frac{3}{5}\),\(\frac{9}{16}\), \(\frac{34}{59}\) and \(\frac{71}{97}\) in ascending ...
Find the value of log\(_{10}\)\(\frac{1}{40}\), given that log10\(_4\) = 0.6021...
In how many ways can a team of 3 girls be selected from 7 girls? ...