\(\frac{-3}{(x + 1)(2 - x)}\)
\(\frac{3}{(x + 1)(2 - x)}\)
\(\frac{-1}{(x + 1)}\)
\(\frac{1}{(x + 1)(x - 2)}\)
Correct answer is A
\(\frac{1}{x + 1}\) - \(\frac{1}{x - 2}\) = \(\frac{x - 2 - x - 1}{(x + 1)(x - 2)}\)
= \(\frac{-3}{(x + 1)(2 - x)}\)
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