A stone, Q is thrown with velocity U at an angle of 75^o to the horizontal. Another stone R is thrown with the same velocity U but with an angle of 15^o to the horizontal. The ranges covered by the stones will be

greater for Q

greater for R

the same for Q and R

greater for the heavier of the two stones

Correct answer is C

Range = \(\frac{U^2sin2\theta}{g}\)

Range_Q = \(\frac{U^2sin150}{g}\)

Range_R = \(\frac{U^2sin30}{g}\)

Since, sin30^o = sin150^o

therefore, R_Q = R_R

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