Find the sum of the first 18 terms of the series 3, 6, 9,...
Find the sum of the first 18 terms of the series 3, 6, 9,..., 36.
505
513
433
635
Correct answer is B
3, 6, 9,..., 36.
a = 3, d = 3, i = 36, n = 18
Sn = \(\frac{n}{2}\) [2a + (n - 1)d
S18 = \(\frac{18}{2}\) [2 x 3 + (18 - 1)3]
= 9[6 + (17 x 3)]
= 9 [6 + 51] = 9(57)
= 513
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