4n + 1
4n - 1
2n + 1
2n - 1
Correct answer is D
Sn=n2−1
Tn=Sn−Sn−1
Sn−1=(n−1)2−1
= n2−2n+1−1
= n2−2n
Sn−Sn−1=(n2−1)−(n2−2n)
= 2n−1
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