x < 12
x < 0 or x < 12
0 < x < 12
1 < x < 2
Correct answer is C
1x > 2 = xx2 > 2
x > 2x2
= 2x2 < x
= 2x2 - x < 0
= x(2x - 10 < 0
Case 1(+, -) = x > 0, 2x - 1 < 0
x > 0, x < 12 (solution)
Case 2(-, 4) = x < 0, 2x - 1 > 0
x < 0, x , 12 = 0