Calculate the length in cm. of the area of a circle of diameter 8cm which subtends an angle of 22 $\frac{1}{2}$ ^o at the centre of the circle

2 $\pi$

$\pi$

$\frac{2}{3}$

$\frac{\pi}{2}$

Correct answer is D

Diameter = 8cm

∴ Radius = 4cm

Length of arc = $\frac{\theta}{360}$ x 2 $\pi$ r but Q = 22 $\frac{1}{2}$

∴ Length $\frac{22\frac{1}{2}}{360}$ x 2 x $\pi$ x 4

= $\frac{22\frac{1}{2} \times 8\pi}{360}$

= $\frac{180}{360}$

= $\frac{\pi}{2}$

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