A resistance thermometer has a resistance of 20 $\Omega$ at 0^oC and 85 $\Omega$ at 100^oC. If its resistance is 52 $\Omega$ in a medium, calculate the corresponding temperature

49.2^oC

60.6^oC

80.0^oC

84.7^oC

Correct answer is A

85 $\Omega$ ........100^oC

52 $\Omega$ ........ $\theta$ ^oC

20 $\Omega$ ........0^oC

$\frac{52 - 20}{85 - 20} = \frac{\theta - 0}{100 - 0}$

$\theta = \frac{32 \times 100}{65} = 49.2^oC$

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