54.00\(\mu F\)
18.00\(\mu F\)
6.00\(\mu F\)
0.17\(\mu F\)
Correct answer is C
\(\frac{1}{c} = \frac{1}{18} + \frac{1}{18} + \frac{1}{18} = \frac{3}{18}\)
c = 6\(\mu F\)
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