R = T(TS2+1)
R = T2(TS2−2)
R = T2(TS2+1)
R = R2(TS2+1)
Correct answer is B
S = √2R+T2RT
Squaring both sides,
S2=2R+T2RT
S2(2RT)=2R+T
2S2RT−2R=T
R=T2TS2−2
= \(\frac{T}{2(TS^{2} - 1)}
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