15
12
−12
(\frac{log_23}{log_27}\)
Correct answer is A
log26 - log23 = log2 (63)
= log22... A
log28 - 2log212
log28 - log2122
log28 - log214
= log2 32... B
AB = log22log232
N.B. log22 = 1
= 15
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