If $\frac{a}{c}$ = $\frac{c}{d}$ = k, find the value of $\frac{3a^2 - ac + c^2}{3b^2 - bd + d^2}$

3k²

2k - k²

$\frac{3b^2k^2 - bk^2d + dk^2}{3b^2 - bd + d^2}$

k²

Correct answer is C

$\frac{a}{c}$ = $\frac{c}{d}$ = k

∴ $\frac{a}{b}$ = bk

$\frac{c}{d}$ = k

∴ c = dk

= $\frac{3a^2 - ac + c^2}{3b^2 - bd + d^2}$

= $\frac{3(bk)^2 - (bk)(dk) + dk^2}{3b^2 - bd + a^2}$

= $\frac{3b^2k^2 - bk^2d + dk^2}{3b^2 - bd + d^2}$

k = $\frac{3b^2k^2 - bk^2d + dk^2}{3b^2 - bd + d^2}$

See all Mathematics questions & answers

See more JAMB questions & answers

If $\frac{a}{c}$ = $\frac{c}{d}$ = k, find the value of $\frac{3a^2 - ac + c^2}{3b^2 - bd + d^2}$

Similar Questions

Aptitude Tests

If ac\frac{a}{c} = cd\frac{c}{d} = k, find the value of 3a2−ac+c23b2−bd+d2\frac{3a^2 - ac + c^2}{3b^2 - bd + d^2}

Similar Questions

Aptitude Tests

If $\frac{a}{c}$ = $\frac{c}{d}$ = k, find the value of $\frac{3a^2 - ac + c^2}{3b^2 - bd + d^2}$