m = 4, n = 2
m = -4, n = -2
m = -4, n =2
m = 4, n = -2
m = -2, n = 4
Correct answer is D
(\(\frac{2}{3}\))m (\(\frac{3}{4}\))n = \(\frac{256}{729}\)
\(\frac{2^m}{4^n}\) x \(\frac{3^n}{3^m}\) = \(\frac{2^{8}}{3^{6}}\)
\(2^{m} \div 2^{2n} = 2^{8}; 3^{n} \div 3^{m} = 3^{-6}\)
m - 2n = 8........(i)
-m + n = -6........(ii)
Solving the equations simultaneously
m = 4, n = -2
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