27
9
127
18
81
Correct answer is A
(log3x)2−6(log3x)+9=0
Let log3x=a.
a2−6a+9=0
a2−3a−3a+9=0
a(a−3)−3(a−3)=0
(a−3)(a−3)=0
⟹a=3(twice)
log3x=3⟹x=33=27
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