Find the acute angle between the straight lines y = x and...
Find the acute angle between the straight lines y = x and y = √3x
15o
30o
45o
60o
Correct answer is A
y = x, Gradient (m1) = 1
y = √3x gradient (m2) = √3
tanθ=m2−m11+m2m1tanθ=√3−11+√3×1=1.73−11+1.73=0.732.73=0.268
θ = Tan-1 (0.268)
= 15o
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