(a), (b), (c)
(c)
None of the choices
All of the above
Correct answer is B
0 < \(\frac{x + 3}{x - 1}\) < 2
Put x = 0, -3 and 9
0 < \(\frac{9 + 3}{9 - 1}\) \(\leq\) 2
i.e. 0 < 1.5 \(\leq\) 2 (true)
but 0 < \(\frac{0 + 3}{0 - 1}\) \(\leq\) 2
i.e. 0 < -3 \(\leq\) 2 (not true)
-3 \(\leq\) 2
-3 is not greater than 0
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