11−x
11+x
1x−1
1x
Correct answer is A
Sum of n terms of Geometric progression is Sn=a(1−rn)1−r
In the given series, a (the first term) = 1 and r (the common ratio) = x.
Sn=1(1−xn)1−x
a = 1, and as n tends to infinity
Sn=11−x
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