A piece of copper of mass 20g at a temperature of 110°...
A piece of copper of mass 20g at a temperature of 110°C was dropped into a mixture of ice and water at 0°C. If the final steady temperature of the mixture is 0°C . Calculate the amount of ice that melted [Specific heat capacity of copper = 0.4 Jg−1K−1, specific latent heat of fusion of ice = 330Jg−1]
0.37g
0.60g
2.40g
2.70g
Correct answer is D
Mice = MCθ
= \(\frac{20 \times 0.4 \times 110}{330}
Heat lost by copper = Heat gained by ice
mcopper c θ = mice L
20 x 0.4 x (110 - 0) = mice x 330
mice = 20×0.4×110330
= 83
= 2.67 g
= 2.70g (to 1 d.p)
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