In the circuit diagram above, calculate the current in th...
In the circuit diagram above, calculate the current in the 12 Ω resistor if the cell has an emf of 12V and an internal resistance of 1Ω
0.8A
1.0A
1.6A
2.4A
Correct answer is D
\(E = I(R + r)\)
\(I = \frac{E}{R + r}\)
\(\frac{1}{R} = \frac{1}{12} + \frac{1}{6} = \frac{1}{4}\)
\(R = 4\Omega\)
\(I = \frac{12}{1 + 4} = \frac{12}{5}\)
= 2.4A
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