If x⁴ - kx³ + 10x² + 1x - 3 is divisible by (x - 1), and if when it is divided by (x + 2) the remainder is 27, find the constants k and 1

k = -7, 1 = -15

k = -15, 1 = -7

k = \(\frac{15}{3}\) , 1 = -7

k = \(\frac{7}{3}\) , 1 = -17

Correct answer is A

If k = -7 is put as -15, the equation x⁴ - kx³ + 10x² + 1x - 3 becomes x⁴ - (7x³) + 10x² + (15)^-3 = x⁴ + 7x³ + 10x² - 15x - 3

This equation is divisible by (x - 1) and (x + 2) with the remainder as 27

k = -7, 1 = -15

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