In the figure, PS = SR and Rx is a tangent to the circle at ...
In the figure, PS = SR and Rx is a tangent to the circle at R, < QRX is equal to 72o. Find angle SPR
A.
20o
B.
36o
C.
72o
D.
30o
E.
15o
Correct answer is B
XRQ = RSQ (Alternate segment)
s = 72o
(80o - 72o = 180o)
a + b + c = 190o = 2b + c = 180o
2b + 108 = 180o
2b = 72o
b = 36o
Similar Questions
Find the integral values of x and y satisfying the inequality 3y + 5x \(\leq\) 15, given that y >...
If the volume of a cube is (8 x 103)cm\(^3\), what is the surface area the cube?...
A group of students took a test and the following frequency table shows the scores above The me...
Simplify \(\frac{2\sqrt{3} + 3\sqrt{5}}{3\sqrt{5} - 2\sqrt{3}}\)...
What are K and L respectively if \(\frac{1}{2}\)(3y - 4x)2 = (8x2 + kxy + Ly2)...
If \(\log_{10}\)(6x - 4) - \(\log_{10}\)2 = 1, solve for x....
In the diagram above, |QR| = 12cm and |QS| = 10cm. If ∠PQR = 90°, ∠RSQ = 90° an...