In the figure, O is the centre of circle PQRS and PS...
In the figure, O is the centre of circle PQRS and PS//RT. If PRT = 135, then PSO is
67\(\frac{1}{2}\)o
22\(\frac{1}{2}\)o
33\(\frac{1}{2}\)o
45o
90o
Correct answer is D
< R = 180o - 45o (sum of angles on a straight line)
< R = < P = 45o (corresponding angles)
< PSO = < P = 45o (\(\bigtriangleup\)PSO is a right angle)
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