TQ is tangent to circle XYTR, < YXT = 32o, RTQ = 40o. ...
TQ is tangent to circle XYTR, < YXT = 32o, RTQ = 40o. find < YTR
108o
121o
140o
148o
Correct answer is A
< TWR = < QTR = 40o (alternate segment)
< TWR = < TXR = 40o(Angles in the same segments)
< YXR = 40o + 32o = 72o
< YXR + < YTR = 180o(Supplementary)
72o + < YTR = 180o
< YTR = 180o - 72o
= 108o
Similar Questions
Which of the following equations represents the graph? ...
Given that 10x = 0.2 and log102 = 0.3010, find x ...
Simplify \(\frac{0.0324 \times 0.00064}{0.48 \times 0.012}\)...
Calculate the gradient (slope) of the joining points (-1, 1) and (2, -2) ...
If y = 3t3 + 2t2 - 7t + 3, find \(\frac{dy}{dt}\) at t = -1...
Find the value of t if the standard deviation of 2t, 3t, 4t, 5t, and 6t is √2 ...
Simplify 2.04 × 3.7 (Leave your answer in 2 decimal place) ...
In the figure, TSP = 100° and PRQ = 20°. Find PQR. ...
Find the next three terms of the sequence; 0, 1, 1, 2, 3, 5, 8... ...