$A battery of e.m.f 3.0V is connected across a potentiometer wire AB of length 10$\Omega m^{-1}$ as illustrated in the diagram above. If the jockey J makes contact at the 30cm mark, determine the resistance of length AJ and voltage across AJ.$

A battery of e.m.f 3.0V is connected across a potentiometer wire AB of length 10 $\Omega m^{-1}$ as illustrated in the diagram above. If the jockey J makes contact at the 30cm mark, determine the resistance of length AJ and voltage across AJ.

3.0 $\Omega$ ; 0.9V

3.0 $\Omega$ ; 3.0V

3.3 $\Omega$ ; 0.3V

3.3 $\Omega$ ; 9.0V

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Correct answer is A

E = 3.0V; $\frac{R}{l} = 10\Omega m^{-1}$

l = 30cm = 0.3m; R = $10\Omega m^{-1} \times 0.3m = 3\Omega$

$\frac{E}{V} = \frac{l_{1}}{l_{2}} \implies \frac{3}{V} = \frac{1}{0.3}$

= $\frac{3\times 0.3}{1} = 0.9V$

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A battery of e.m.f 3.0V is connected across a potentiometer wire AB of length 10 $\Omega m^{-1}$ as illustrated in the diagram above. If the jockey J makes contact at the 30cm mark, determine the resistance of length AJ and voltage across AJ.

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A battery of e.m.f 3.0V is connected across a potentiometer wire AB of length 10 $\Omega m^{-1}$ as illustrated in the diagram above. If the jockey J makes contact at the 30cm mark, determine the resistance of length AJ and voltage across AJ.