A supply of 400V is connected across capacitors of 3μf...
A supply of 400V is connected across capacitors of 3μf and 6μf in series. Calculate the charge
A.
8 x 10\(^{-4}\)C
B.
4 x 10\(^{-2}\)C
C.
8 x 10\(^{-3}\)C
D.
4 x 10\(^{-8}\)C
Correct answer is A
| C\(_T\) | = | C\(_1\) × C\(_2\)
C\(_1\) + C\(_2\) |
| = | 3 × 6
3 + 6 |
= \(\frac{18}{9}\) = 2μf
Q = CV
⇒ 2 × 10\(^{-6}\) × 400
⇒ 800 × 10\(^{-6}\)C = 8 × 10\(^{-4}\)C
Similar Questions
A piece of wood is floating on water. The forces acting on the wood are ...
Which of the following electromagnetic waves has the highest frequency? ...
Iron at 30oC feels colder to the hand than wood at 28oC because...
If the frequency of the ac. circuit illustrated above is 500/π Hz what would be the reactance in ...