-2\(\frac{1}{3}\)
-2\(\frac{1}{4}\)
2\(\frac{1}{8}\)
2\(\frac{3}{4}\)
Correct answer is D
1\(\frac{1}{2} + 2\frac{1}{3} \times \frac{3}{4} - \frac{1}{2}\)
\(\frac{3}{2} + \frac{7}{3} \times \frac{3}{4} - \frac{1}{2} = \frac{3}{2} + \frac{7}{4} - \frac{1}{2}\)
= \(\frac{6 + 7 - 2}{4} = \frac{11}{4}\)
= 2\(\frac{3}{4}\)
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