A ray of light traveling from glass into ethyl alcohol is incident at the boundary at an angle of incidence 30 $^o$ . Calculate the angle of refraction.

[Refractive index of glass =1.5; refractive index of ethyl alcohol = 1.36]

27 $^o$

33.5 $^o$

51.7 $^o$

72.8 $^o$

Correct answer is B

The angle of incidence l = 30º
The angle of refraction , r =?
The refractive index of glass ng = 1.5
The refractive index of ethyl alcohol, ne = 1.36
from snell's law :

$\frac{n_e}{n_g} = \frac{sini}{sinr}$

$\frac{1.36}{1.5} = \frac{sin30º}{sinr}$

1.36sinr = 1.5 x sin30º

sinr = $\frac{1.5 \times sin30º}{1.36}$

sinr = 0.5515

r = $sin^{-1}$ (0.5515)

r = 33.5º

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A ray of light traveling from glass into ethyl alcohol is incident at the boundary at an angle of incidence 30 $^o$ . Calculate the angle of refraction.

[Refractive index of glass =1.5; refractive index of ethyl alcohol = 1.36]

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A ray of light traveling from glass into ethyl alcohol is incident at the boundary at an angle of incidence 30o^o. Calculate the angle of refraction. [Refractive index of glass =1.5; refractive index of ethyl alcohol = 1.36]

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A ray of light traveling from glass into ethyl alcohol is incident at the boundary at an angle of incidence 30 $^o$ . Calculate the angle of refraction.

[Refractive index of glass =1.5; refractive index of ethyl alcohol = 1.36]