In an electric circuit, an inductor of inductance 0...
In an electric circuit, an inductor of inductance 0.5 H and resistance 50Ω is connected to an alternating current source of frequency 60 Hz. Calculate the impedance of the circuit.
50.0Ω
450.5 Ω
195.0 Ω
1950.1 Ω
Correct answer is C
The impedance of a R-L circuit is given by:
Z = √(R2 + XL2) ----------- eqn(1)
where Z is the impedance,
R is the resistance, and
XL is the inductive reactance
XL = 2πfL ------------ eqn(2)
where f is the frequency
From eqn(2),
XL = 2 * π * 60 * 0.5
= 60π
Also, from eqn(1),
Z = √(502 + (60π)2)
Z = 195.0Ω
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