In an electric circuit, an inductor of inductance 0...
In an electric circuit, an inductor of inductance 0.5 H and resistance 50\(\Omega\) is connected to an alternating current source of frequency 60 Hz. Calculate the impedance of the circuit.
50.0\(\Omega\)
450.5 \(\Omega\)
195.0 \(\Omega\)
1950.1 \(\Omega\)
Correct answer is C
The impedance of a R-L circuit is given by:
Z = √(R\(^2\) + XL\(^2\)) ----------- eqn(1)
where Z is the impedance,
R is the resistance, and
XL is the inductive reactance
XL = 2πfL ------------ eqn(2)
where f is the frequency
From eqn(2),
XL = 2 * π * 60 * 0.5
= 60π
Also, from eqn(1),
Z = √(50\(^2\) + (60π)\(^2\))
Z = 195.0Ω
The height at which the atmosphere ceases to exist is about 80km. If the atmospheric pressure o...
Which of the following statements is true of ultra violet radiations? It ...
Which of the following defects of vision is as a result of the eye ball being too long? ...
Two capacitors, each of capacitance 2\(\mu\)F are connected in parallel. If the p.d across them...
The reason for laminating the soft iron core of a transformer is to? ...