Calculate the mass of ice that would melt when 2kg of cop...
Calculate the mass of ice that would melt when 2kg of copper is quickly transferred from boiling water to a block of ice without heat loss (specific heat capacity of copper = 400Jkg\(^{1}\)k\(^{-1}\), latent heat of fusion of ice = 3.3 x 10\(^{5}\)Jkg\(^{-1}\))
\(\frac{8}{33}\)kg
\(\frac{3.3}{80}\)kg
\(\frac{80}{33}\)kg
\(\frac{3.3}{8}\)kg
Correct answer is A
mc\(\Delta\theta\) = m\(\lambda\)f
2 x 400 (100 - 0) = m(3.3 x 10\(^{5}\))
m = \(\frac{2 \times 400 \times 100}{3.3 \times 10^{5}} = \frac{8}{33}\)kg