1.5 x \(10^6Jkg^-1\)
1.35 x \(10^6Jkg^-1\)
1.5 x \(10^5Jkg^-1\)
4.5 x \(10^2Jkg^-1\)
3 x \(10^2Jkg^-1\)
Correct answer is A
Pt=mI; I=\(\frac{1500\times300}{0.3}=1.5\times10^6Jkg^-1\)
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