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Given that (x + 2)(x2 - 3x + 2) + 2(x + 2)(x - 1)...

Given that (x + 2)(x2 - 3x + 2) + 2(x + 2)(x - 1) = (x + 2) M, find M

A.

(x + 2)2

B.

x(x + 2)

C.

xv + 2

D.

x2 - x

Correct answer is D

(x = 2)(x2 - 3x + 2) + 2(x + 2)(x - 1) = (x + 2)m

(m + 2)[(x2 - 3x + 2) + 2(x - 1)] = (x + 2)M

divide both side by (x + 2)

(x2 - 3x + 2) + 2(x - 1) = M

x2 - 3x + 2 + 2x - 2 = M

x2 - 3x + 2 + 2x - 2 = M

x2 - 3x + 2x = M

x2 - x = M

M = x2 - x