The equation of the line through the points (4,2) and (-8...
The equation of the line through the points (4,2) and (-8, -2) is 3y = px + q, where p and q are constants. Find the value of p.
1
2
3
9
Correct answer is A
Using the two - point from
y−y1y2−y1=x−x1x2−x1
y−2−2−2=x−4−8−4
y−2−4=x−4−12
−12(y−2)−4 = x - 4
3(y -2) = x -4
3y - 6 = x - 4
3y = x - 4 + 6
3y = x + 2...
By comparing the equations;
3y = px + , p = 1
Simplify x−7x2−9 x x2−3xx2−49...
P, R and S lie on a circle center as shown above while Q lies outside the circle. Find ∠PSO ...
In the diagram above, ∠SPR = P and ∠SQR = 2x. Find x in terms of P ...
Given that 2p - m = 6 and 2p + 4m = 1, find the value of (4p + 3m). ...
A cuboid has a diagonal of length 9cm and a square base of side 4cm. What is its height? ...