Three consecutive terms of a geometric progression are gi...
Three consecutive terms of a geometric progression are give as n - 2, n and n + 3. Find the common ratio
32
23
12
14
Correct answer is A
hn−2=n+3n
n2 = (n + 3) (n - 2)
n2 = n2 + n - 6
n2 + n - 6 - n2 = 0
n - 6 = 0
n = 6
Common ratio: nn−2=66−2=64 = 32
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