If p varies inversely as the square of...
If p varies inversely as the square of q and p=8 when q=4, find q when p =32
\(\pm\)16
\(\pm\)8
\(\pm\)4
\(\pm\)2
Correct answer is D
p ∝ 1/q
p = k/q
K = q\(^2\)p
= 4\(^2\)(8)
∴p = 128/q
32 = 128/q
q\(^2\) = 128/32
q\(^2\) = 4
q = √4 = \(\pm\) 2
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