A line L passing through the point (6, -13) is parallel t...
A line L passing through the point (6, -13) is parallel to the line which passes through (7, 4) and (-3, 9). Find the equation of the line L.
y = 12x−10
y = −12x+10
y = −12x−10
y = 12x+10
Correct answer is C
(7, 4) and (-3, 9) = (y1,x1)(y2,x2)
slopem1 of the points(7, 4) and (-3, 9) = y2−y1x2−x1
m1=9−4−3−7=5−10=−12
m1=m2 ( condition for parallelism)
Since the line L passes through the point (6, -13) and is parallel to the points (7, 4) and (-3, 9)
−12=y−(−13)x−6
= −12=y+13x−6
= −12(x−6)=y+13
−12x+3=y+13
= −12x+3−13=y
∴ y = −12x−10