\(\frac{ah}{2l - h}\)
\(\frac{2l - h}{al}\)
\(\frac{al}{2l - h}\)
\(\frac{al}{2 - h}\)
Correct answer is A
lb = \(\frac{1}{2} (a + b)h
2lb = ah + bh
2lb - bh = ah
\(\frac{b(2l - h)}{2l - h} = \frac{ah}{2l - h}\)
b = \(\frac{ah}{2l - h}\)
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