The angle of a sector of a circle of radius 3.4 cm is 115°. Find the area of the sector.
\((Take \pi = \frac{22}{7})\)
A.
\(11.6cm^2\)
B.
\(12.7cm^2\)
C.
\(10.2cm^2\)
D.
\(9.4cm^2\)
Correct answer is A
\(\theta = 115° , radius = 3.4cm^2\)
Area of a sector = \(\frac{\theta}{360} \times \pi r^2\)
= \(\frac{115}{360} \times \frac{22}{7} \times 3.4\times 3.4\)
= \(\frac{29246.4}{2520}\)
= \(11.6cm^2\)
