In recharging a lead-acid accumulator, the reaction at th...
In recharging a lead-acid accumulator, the reaction at the cathode can be represented as
Pb2+(aq) + SO2-4(aq) →PbSO4(s)
Pb2+(aq) + 2e- →Pb(s)
Pb2+(aq) + 2H2O(l) → PbO2(s) + 4H+(aq) + 4e-
Pb(s) → Pb2+(aq) + 2e-
Correct answer is B
In lead acid ,lead dissociates at the cathode Pb2+(aq) + 2e- →Pb(s)
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