What quantity of copper will be deposited by the same quantity of electricity that deposited 9.0g of aluminum? (A = 27, Cu = 64)
A.
64g
B.
32g
C.
7.1g
D.
6.4g
E.
3.2g
Correct answer is B
Al has valency of 3+:
3F will deposit 27g
xF will deposit 9g
cross multiply → \(\frac{9g * 3F}{27g}\)
: 1F = 9g
Cu has valency of 2+:
2F will deposit 64g
1F will deposit xg
cross multiply → \(\frac{64g * 1F}{2F}\)
: 1F = 32g
