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Consider the following equation; Cr2O7(aq)

Consider the following equation; Cr2O7(aq)2- + 14H+(aq) + 6e- → 2Cr3+(aq) + 7H2O(I). The oxidation number of chromium changes from

A.

-2 to + 3

B.

- 2 to + 6

C.

+ 6 to + 3

D.

+ 7 to + 6

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Correct answer is C

No explanation has been provided for this answer.

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