What is the product Cx Hy in the following equation? \(C_...
What is the product Cx Hy in the following equation? \(C_{10}H_{22}\) → \(C_{8}H_{18}\) + CxHy
butene
octane
ethene
decane
Correct answer is C
\(C_{10}H_{22}\) → \(C_{8}H_{18}\) + CxHy
\(C_{10}H_{22}\) → \(C_{8}H_{18}\) + (\(C_2H_4\)) ⇒⇒ Ethene.