Consider the reaction represented by the following equation: Na₂CO_3(aq) + 2HCl_(aq) $\longrightarrow$ 2NaCl_(aq) + H₂O_(l) + CO_2(g) . What volume of 0.02 mol dm^-3 Na₂CO_3(aq) would be required to completely neutralize 40 cm³ of 0.10 mol dm^-3 HCl_(aq)?

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