H\(_2\) S\(_{(g)}\) + Cl\(_{2(g)}\) → 2HCl\(_{(g)}\) + S\(_{(g)}\) In the reaction above, the substance that is reduced is

H\(_2\)S

HCl

Cl\(_2\)

View answer & explanation

Correct answer is D

H \(_2\) S + Cl \(_2\) → 2HCl + S

Please note: substance oxidized or reduced are always the reactants. So, one can easily cross out the two products.

Reduction is

1. Addition of hydrogen

2. Removal of Oxygen

3. Addition of Electron

Oxidation is

1. Removal of hydrogen

2. Addition of hydrogen

3. Removal of Electron

From the question we can see that H was added to Cl in the product, thereby making hydrogen to be removed from S in the reactant hence S is oxidized as a result of the removal of hydrogen and Cl \(_2\) has been reduced due to addition of hydrogen.

Cl \(_2\) is reduced

See all Chemistry questions & answers

See more JAMB questions & answers

Aptitude Tests

Situational Judgement Questions and Answers

Spatial Reasoning Questions and Answers

Quantitative Reasoning Questions and Answers

Numerical Reasoning Questions and Answers

Microsoft Office Questions and Answers

Personality Test

Logical Reasoning Questions and Answers

Puzzles Questions and Answers

Abstract Reasoning Questions and Answers

Verbal Reasoning Questions and Answers

Nigeria General Knowledge Questions and Answers

Typing Speed and Accuracy Test

Data Interpretation Questions and Answers

See all →

View latest jobs in Nigeria today

H\(_2\) S\(_{(g)}\) + Cl\(_{2(g)}\) → 2HCl\(_{(g)}\) + S\(_{(g)}\) In the reaction above, the substance that is reduced is

Similar Questions

Aptitude Tests