A hydrocarbon contained 14.3% hydrogen. The empirical for...
A hydrocarbon contained 14.3% hydrogen. The empirical formula for the hydrocarbon is [H= 1.0, C= 12.0]
\(CH\)
\(CH_{2}\)
\(CH_{3}\)
\(CH_{4}\)
Correct answer is B
The percentage of Carbon in the compound is (100 - 14.3)% = 85.7%
C : H
\(\frac{85.7}{12.0} : \frac{14.3}{1.0}\)
\( 7.14 : 14.3\)
\(\frac{7.14}{7.14} : \frac{14.3}{7.14}\)
\(\approxeq 1 : 2\)
Therefore, the empirical formula is \(CH_{2}\).
What is the sum of the oxidation numbers in a neutral compound? ...
How many mole of AgNO 3 are there in 500cm3 of 0.01MAgNO3 solution?...
The relative molar mass of a gaseous hydrocarbon is 30. Determine its vapour density. ...
The main characteristic feature of transition metals is that they...
The type of isomerism shown by cis- and trans- isomers is ...
What is the chemical symbol for Krypton? ...
Which of the following reactions does not take place in the smelting of iron in a blast furnace? ...