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$_2$ + O

$_2$ &n...

2H $_2$ + O $_2$ → 2H $_2$ O

From the...

2H $_2$ + O $_2$ → 2H $_2$ O

From the equation above, calculate the volume of unreacted oxygen gas if a mixture of 50cm $^3$ of hydroden and 75cm $^3$ of oxygen are involved

A.

85cm $^3$

B.

50cm $^3$

C.

125cm $^3$

D.

55cm $^3$

View answer & explanation

Correct answer is B

Since 2 mol H $_2$ reacted with 1 mol of O $_2$

: 50cm $^3$ of hydrogen reacted with 25cm $^3$ of oxygen

Remainder oxygen = Supplied amount - Reacted amount → 75cm $^3$ - 25cm $^3$

= 50cm $^3$

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