2H2 + O2 → 2H2O
From the...
2H2 + O2 → 2H2O
From the equation above, calculate the volume of unreacted oxygen gas if a mixture of 50cm3 of hydroden and 75cm3 of oxygen are involved
85cm3
50cm3
125cm3
55cm3
Correct answer is B
Since 2 mol H2 reacted with 1 mol of O2
: 50cm3 of hydrogen reacted with 25cm3 of oxygen
Remainder oxygen = Supplied amount - Reacted amount → 75cm3 - 25cm3
= 50cm3
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